16y^2-9x^2-64y-36x=116

Write the equation in graghing fom, identify the center and the slope of the asymptotes. Then graph each hyperbola.

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1 Answer

16y^2 -64y -9x^2 -36x=116

become (4y-8)^2 - (3x-6)^2 =116 -64 +36=88

or   [4(y-2)]^2 - [3(x-2)]^2 -88=0
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