y = mx+b

the line passing through the point (6, -1) and perpendicular to y = 1/7x - 9
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2 Answers

line thru point=(6,-1) & perpendikular tu y=1/7

slope=-1/other slope=-7

y=-7x+konst

projekt line bak from x=6 tu x=0

deltax=-6, deltay=slope*deltax=(-7)*(-6)=+42

y-intersept=-1+42=41

y=-7x+41
by
Here slope=1/7

slope of the perpendicular line =-1/(1/7)=-7

y=mx+b

y=-7x+b

-1=(-7)(6)+b

-1+42=b

b=41

y=-7x+41 is the required equation.
by Level 8 User (32.3k points)

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