find the derivative of 1/ sqroot of 2x^3+1?

derivatives and square roots
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If y=1/√(2x3+1), let u=2x3+1, then du/dx=6x2 and y=u-½, so dy/du=-½u-3/2.

dy/dx=dy/du × du/dx=(-½u-3/2)6x2=-3x2u-3/2=-3x2/√(2x3+1)3.

Therefore the derivative of 1/√(2x3+1) is -3x2/√(2x3+1)3.

by Top Rated User (1.2m points)

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