A dice is flipped twelve times. What is the probability that less than two fives appear?

in Word Problem Answers by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

The probability of flipping a five is ⅙, so the probability of not flipping a five is ⅚.

The probability of no fives at all is (⅚)¹².

The probability of only one five is 12(⅚)¹¹(⅙) because the single five can come first, second, third, etc., but nowhere else.

So the probability of less than 2 fives is the sum of no-fives and one-five:

(⅚)¹²+12(⅚)¹¹(⅙)=(⅚)¹¹(⅚+2)=0.3813 or about 38.13%.

by Top Rated User (1.2m points)

Related questions

1 answer
asked Mar 2, 2016 in Word Problem Answers by Mathical Level 10 User (57.4k points) | 2.0k views
1 answer
asked Jan 25, 2012 in Algebra 1 Answers by Dyslexic-man Level 1 User (860 points) | 736 views
Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
87,516 questions
100,279 answers
2,420 comments
731,831 users