First, let try to find some squared integers nearer to 224. 14x14=10x(10+4+4)+4x4=10x18+4x4=180+16=196, 15x15=1x2x100+5x5=200+25=225, or 15x15=10x(10+5+5)+5x5=10x20+25=200+25=225, 16x16=10x(10+6+6)+6x6=10x22+6x6=220+36=256. Judging from the results obtained above, the two integers would be somewhere close to 14, 15 and 16. The ones-digit of 224 is 4. This indicates the ones-digit of the first integer is 4, and that of the second is 6. Because 4x6=24, but the ones-digits of the procucts of other even consecutive integers are 0 or 8. Therefore, the two consecutive even integers will be 14 and 16. Let check the product. 14x16=10x(10+4+6)+4x6=10x20+24=200+24=224. 14 and 16 are correct integers. Since the product of two integers with the same signs is positive. -14 and -16 are also the integers that satisfy the conditions. Therfore, the answers are two sets of consecutive even integers: {14,16}, and {-14,-16}.