ann rain is norm dist w/ a mn of 129& st. dev. of 12, ? is prob of rain in given yr being > 110 in

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Z score=(110-129)/12=-1.583. This corresponds to 1-P(1.583)=1-0.9432. This is the probability of less than 110" of rainfall. The probability of rainfall being in excess of 110" is 1-(1-0.9432)=0.9432 or about 94.3%.

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