I got stuck with the following (sorry if it has been answered, but I could't find it):

we have:
logax= lnx / lna  -- "change of base"
and
ln( x1 * x2 ) = lnx1 + lnx2

show that loga(x1 * x2 ) = loga(x1) + loga(x2)

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1 Answer

log(x*y)=log(x)+log(y) is tru for all logs,

base av log dont matter...same ops, same rules, just differ numbers

log defined tu be the power yu gotta raes base tu tu get x
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