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In any triangle ABC:

AB+BC>AC; AB+AC>BC; AC+BC>AB. (The sum of the lengths of any two sides is greater than the length of the remaining side.)

So AB<AC+BC, so AB>AC+BC is false. BC<AB+AC, so  BC>AB+AC is also false.

AB+AC=BC+AC, AB=BC (given), so AB+AC=BC+AC is true.

AB+BC=AB+AC, 2AB=AB+AC, AB=AC is false (in general) since only two sides AB and BC are given to be equal. If it were true ABC would be an equilateral triangle AB=BC=AC.

by Top Rated User (1.2m points)

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