I need to know what the equations would look like in this set up.
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ok, you have the slope -5, insert that into y=(slope)*X + C,  C is not a variable, it is a coefficient.

You get y=-5*x + c

you are also given the (x,y) values, replace x and y with their values.

-8=-5*(-3) + c

now we solve for c.

(-8 = 15 + c) = (c + 15 = -8), all i did swap the right and left sides.  That didn't change the equation at all.

now, we want c alone.  So, we subtract 15 from but sides.

c + 15 - 15 = -8 -15,

c = -23.  now, you can check the answer

y = (slope)*x + c, we now know all the values.  y = -8, x = -3, slope = -5, c = -23

insert known values.

-8 = (-5)*-3 + (-23),  check that the equation in balanced

-8 = 15 + -(-23)

-8 = -8

FINAL STEP: insert just the slope value and the coefficient into  y = (slope)*x +c

y = (-5)*x -8

you can now graph this and find (x,y) coordinates by placing a new value for x and then solve for y.  If the equation balances, you are good!!!
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