About fraction

Question

Roger and sally share a sum of $60 . After their uncle gave each of them$ 16 more, Roger had 10/13 of the amount of Sally had. What fraction of the sum of $ 60, did Roger receive at first ?

Answer 1

Let R=Roger's share then Sally's share is 60-R.

They each receive an extra $16, so Roger now has R+16 and Sally 76-R.

Roger has 10/13 of Sally's share so R+16=10(76-R)/13.

Therefore:

13(R+16)=10(76-R),

13R+208=760-10R,

23R=760-208=552, R, Roger's share=552/23=$24, so Sally's share is 60-24=$36.