if h(x)=sqrt(5+10f(x)), where f(9)=2 and f'(9)=8, find h'(9)

I need help in finding h'(9) when h(x)=sqrt(5+10f(x)), where f(9)=2 and f'(9)=8. Please show work, thank you!
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1 Answer

h(x)=√(5+10f(x))

h'(x)=½.10f'(x)/√(5+10f(x))=5f'(x)/√(5+10f(x)).

When x=9:

h'(9)=5f'(9)/√(5+10f(9))=40/√(5+20)=40/5=8.
by Top Rated User (1.2m points)

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