tn=bn+c, so t1=b+c and t2=2b+c.
But t1=3x+8 and t2=x-2, therefore:
b+c=3x+8 and 2b+c=x-2. Hence (2b+c)-(b+c)=b=3x+8-(x-2)=2x+10.
tn-1=b(n-1)+c; tn-tn-1=bn+c-b(n-1)-c=bn+c-bn+b-c=b.
145-141=4, no matter what n is, so it must apply to the last two terms (given). Therefore b=4.
Therefore 2x+10=4, 2x=-6, x=-3 QED.