f(t) = e^at lapace using integral in mathlab

f(t) = e^at lapace using integral in mathlab
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1 Answer

Laplace transform for eat is 1/(s-a).

ℒ{f(t)}(s)=0∫∞f(t)e-stdt by definition.

Therefore ℒ{eat}(s)=t=0∫t=∞eate-stdt=t=0∫t=∞e(a-s)tdt=

(1/(a-s))[e(a-s)t]0∞=(1/(a-s))(0-1)=1/(s-a) provided a-s<0 that is, s>a.

I don't have access to MATLAB or MATHLAB.

by Top Rated User (1.2m points)

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