Find the intercepts of (x^2)(y) - x^2 + 4y = 0

Since this cannot be plugged into the calculator, if someone could please explain the steps to go through in problems such as these, I would be very appreciative!
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1 Answer

x2y-x2+4y=0. To find the x-intercepts, set y=0: -x2=0, so x=0 is the x-intercept at (0,0).

To find the y-intercepts, set x=0: 4y=0, y=0 is the y-intercept at (0,0). Therefore (0,0) is both intercepts. 

by Top Rated User (1.2m points)

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