<!--[if !supportLists]-->1.    <!--[endif]-->The average height of the International Space Station is 400km above the Earth. An astronaut on board the International Space Station sights along a tangent line to Earth, viewing Houston Space Center. If the diameter of the Earth is approximately 12,800 km, how far is the astronaut from the Space Center. Draw/Illustrate the problem

by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

A right triangle is formed by joining the space station to the centre of the earth (400+6400=6800km). The tangent point is distance 6400km from the centre of the earth (radius) and the line of sight makes a right angle with the radius. So the distance between the space station and the tangent point is √(68002-64002)=√5280000=2297.8km approx.

In the picture the blue circle represents the earth, point A is the astronaut at the space station and H represents the location of Houston. AH is the distance required, OH is a radius=12800/2=6400km. AO=6400+400=6800km (not to scale). ∠AHO is a right angle.

by Top Rated User (1.2m points)

Related questions

1 answer
1 answer
asked Jun 24, 2014 in Calculus Answers by kim_gallego10@yahoo.com | 846 views
1 answer
asked Jun 24, 2014 in Calculus Answers by kim_gallego10@yahoo.com | 597 views
1 answer
asked Jun 14, 2016 in Other Math Topics by shakthi abi | 573 views
Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
87,516 questions
100,279 answers
2,420 comments
731,891 users