x^2-3x can be shown as (x+a)^2 +b where

solve for a & b pleaseeee. this is a pre-calculus question
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1 Answer

x^2-3x=x^2-3x+9/4-9/4=(x-3/2)^2-9/4, so a=-3/2 and b=-9/4.

[It can also be shown as x(x-3).]
by Top Rated User (1.2m points)

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