FIXED POINT ITERATION
We are not given a starting value h₀, so let h₀=0, then:
f(h₀)=0.605946 approx when we substitute for V and r.
Now substitute this value for h into the square root expression to get h₁:
We have achieved 4 decimal place accuracy with this iteration so the solution is h=0.6906.
If h₀=1 as possibly indicated in the table, we get f(h₀)=0.836961
So, again, h=0.6906 is the solution. Note that we needed more iterations using h₀=1 than we did for h₀=0.