This is a trig problem. Fairly simple

This is a trigonometry question. The problem is on in the link. Please show work so I can understand what you are doing.

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1 Answer

Let the horizontal triangle be ABC where C is the bottom corner of the building.

∠ACB=180-(82+51)=47°.

Sine Rule:

50/sin47=AC/sin51, AC=50sin51/sin47=53.15m approx.

Height of building h/AC=tan20, h=53.15tan20=19.34m approx.

by Top Rated User (1.2m points)

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