can you prove this problem using trigonometric identities? secƟ-sinƟ tanƟ=cosƟ

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muneepenee · Answer 1 · 2014-07-02T11:51:14+0000

sekant(x) -kosine = sine*tangent

(1/kosine) -kosine = sine*sine/kosine

1 - kosine^2 =sine*sine=sine^2

or sine^2 +kosine^2=1

standard from geometry av rite triangel

John Marsh · Answer 2 · 2014-07-03T09:58:55+0000

Given secƟ-sinƟ tanƟ=cosƟ

LHS
secƟ-sinƟ tanƟ
1/(cosƟ)-sinƟ(sinƟ/cosƟ)
[1-sin^2Ɵ]/cosƟ
cos^2Ɵ/cosƟ
cosƟ

Hence LHS=RHS

Trig Help - http://math.tutorvista.com/trigonometry.html

can you prove this problem using trigonometric identities? secƟ-sinƟ tanƟ=cosƟ

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