How to do (x^4+3x^3+x^2+9x-6)/(x^2+3x-2) with polynomial long division?

I know that the answer to the problem is x^2+3 but I don't know how to show getting 0x in the work of the problem. Thanks for any help.
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1 Answer

                 x²         +3

x²+3x-2 ) x⁴+3x³+x²+9x-6

              -(x⁴+3x³-2x²)

                              3x²+9x-6

                           -(3x²+9x-6)

So the answer is x²+3 (no remainder).

by Top Rated User (1.2m points)

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