How do I solve the following equation?
7sin(4x) = 7cos(2x)
I know of the trig identity where sin(2x) = 2sin(x)cos(x), but I'm not sure how this would apply for this particular problem where it's doubled.
I am applying it to an Area Between Curves question, where I am asked to solve for the area enclosed by the curves:
y = 7sin(4x), y = 7cos(2x), x = 0, x = pi/4
Thank you!