this problem is hard can someone answer this, i need the answer really bad cause ive been strugling on this answer quite a while please answer it!
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2 Answers

1. Assume this is 3/(5y-11)=8/(3y+4).

Cross-multiply: 3(3y+4)=8(5y-11).

Expand brackets: 9y+12=40y-88.

Subtract 9y from each side: 12=31y-88.

Add 88 to each side: 100=31y so y=100/31.

2. Assume (3/5)y-11=(8/3)y+4.

Multiply through by 15: 9y-165=40y+60.

Add 165 to each side: 9y=40y+215.

Subtract 40y from each side: -31y=215 or 31y=-215, y=215/31.

3. Another interpretation: assume 3/(5y)-11=8/(3y)+4.

Multiply through by 15y: 9-165y=40+60y.

-215y=31, y=-31/215.

The solution depends on which interpretation is intended.
by Top Rated User (1.2m points)

Given 3/(5y-11)=8/(3y+4)

3(3y+4)=8(5y-11)

9y+12=40y-88

9y+12-40y+88=0

-31y+100=0

-31y=-100

y=100/31

Pre Algebra Help

 

by Level 8 User (30.1k points)

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