J to T : 5x+8
C to J: 7x+2
Therefore, distance between C to T = (C to J) + (J to T) = (7x + 2) + (5x+8) = 12x + 10 ---------------------(i)
Also, distance between C to T is 70 units. ----------------------(ii)
From (i) and (ii) we get:
12x+10 = 70
=> 12x = 70-10
=>12x = 60
=> x = 60/12
=> x = 5
Therefore distance between J to T = 5x+8
=>distance between J to T = 5(5) + 8 = 25+8 = 33 units