Calculate the specific heat for the following:

 

a 48.2 g sample of a metal that absorbs 345 j when its temp increases from 35.0 c to 57.9 c
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1 Answer

48.2 gram, delta temper=22.9 deg (sentigrade?????)

take 345 jues

heet kapasity=345/(48.2*22.9)

=345/1103.78

=0.312562286

or bout 0.313 jues per gram-degree
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