How many numbers between 24 and 83 are evenly divisible by 6? (with no remainder)

Question

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Answer 1

You have to find the first and the last number in range that is divisible by 6,

So the numbers are 24 and 78

Now use A.P

78 = 24 + (n-1) *6

=> (78-24)/6 = n-1

=>54/6 = n-1

=> n = 9 +1

=> n = 10

Answer is 10.

and numbers are 24,30,36 42,48,54,60,66, 72  and 78

Answer 2

24 and 78 are both divisible exactly by 6, that’s 4×6 and 13×6. That’s all the numbers between 4 and 13–10 numbers so there are 10 numbers divisible by 6 between 24 and 83 (inclusive).

But if you only want the even numbers then we have 4, 6, 8, 10, 12, only 5 numbers. So only 5 numbers (24, 36, 48, 60, 72) are evenly divisible by 6.

Answer 3

10

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24, 30, 36, 42, 48, 54, 60, 66, 72, 78