Write the equation of parabola given the characteristics
Vertex (-6,-1)
Focus (-6,2)

Vertex (9,-2)
Focus (5,-2)
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y-k=a(x-h)² where vertex is V(h,k) and focus is F(h,k+1/(4a)) for a vertical parabola. 

x-h=a(y-k)² where vertex is V(h,k) and focus is F(h+1/(4a),k) for a horizontal parabola.

|1/(4a)| is the distance between the vertex and the focus and the perpendicular distance between the vertex and the directrix line.

(1) V(-6,-1), F(-6,2) Vertical parabola (red).

y+1=a(x+6)²

-1+1/(4a)=2, 1/(4a)=3, a=1/12.

y+1=(x+6)²/12,

y=(x²+12x+36)/12-1=x²/12+x+2.

y=x²/12+x+2.

(2) V(9,-2), F(5,-2) Horizontal parabola (blue).

x-9=a(y+2)²

9+1/(4a)=5, 1/(4a)=-4, a=-1/16.

x-9=-(y+2)²/16,

x=-(y²+4y+4)/16+9=-y²/16-y/4-1/4+9,

x=-y²/16-y/4+35/4.

Parabolas shown with focus and directrix in the same colour.

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