I'm a bit stuck can anyone help?

by Level 1 User (520 points)

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

Let’s find the length and width of the enclosing rectangle:

Length=1+5+1=7. Width=5. Area=7×5=35cm².

The area of each narrow rectangle is 5cm² and there are 4 of them, making 20cm².

So the shaded area=35-20=15cm².

Another way to solve it is to find the dimensions of the shaded area. Width=5-1-1=3cm. Length=5cm. So area=3×5=15cm².

by Top Rated User (711k points)

Related questions

1 answer
asked Nov 19 by Aajs1491 Level 1 User (520 points) | 31 views
1 answer
asked Mar 30, 2015 in Geometry Answers by haileygreen13 Level 1 User (120 points) | 124 views
0 answers
Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
84,412 questions
89,225 answers
1,990 comments
7,511 users