Ray PL lies in the interiof of angle RPH; m angle RPL=X-5 and m angle LPH=2x+18. If m angle hPR=58, find the measure of the smallest angle formed.

The answer is m angle RPL=10. I made it an effort but I do not know how it arrive at this answer, Would you show solution?
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1 Answer

∠HPR=∠RPL+∠LPH,

58=x-5+2x+18,

58=3x+13,

45=3x,

15=x.

So ∠RPL=x-5=15-5=10. The other angle is larger.

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