Find the standard deviation for the given sample data. 2, 3, 5, 13, 22, 35, 60, 86, 101, 122

Question

months employees have worked at resturant

Answer 1

First sum the data: 449 (10 data elements). Mean=449/10=44.9.

X	X-44.9	(X-44.9)2
2	-42.9	1840.41
3	-41.9	1755.61
5	-39.9	1592.01
13	-31.9	1017.61
22	-22.9	524.41 6730.05
35	-9.9	98.01
60	15.1	228.01
86	41.1	1689.21
101	56.1	3147.21
122	77.1	5944.41
449	0	17836.90

Variance=17836.90/10=1783.69, standard deviation=√1783.69=42.23 months.

This is a very large standard deviation considering the mean is 44.9 months.