Find the area of the missing square off of leg (a) if the area of one square is 225 and the area of another is 81? Show work by hand.
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My guess is that you have a right triangle with hypotenuse length=225 and one of the legs with length 81, so using Pythagoras’ Theorem, the square of other leg is 225-81=144. So the other leg is √144=12 in length.

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