What is the eccentricity of the hyperbola given by the equation y^2/100-x^2/36=1

What is the eccentricity of the hyperbola given by the equation y^2/100-x^2/36=1
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The eccentricity of a hyperbola=√(1+b2/a2) where a>b and y2/a2-x2/b2=1 is the equation of the hyperbola. So in the given hyperbola, a=10 and b=6, so b/a=0.6 and the eccentricity is √1.36=1.166 approx.

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