Please make b the subject 1/3a + 6b = 2b - 3c(3b/2 - 5)

Please make b the subject of the equation.
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1 Answer

⅓a+6b=2b-3c(3b/2-5),

⅓a+4b+3c(3b/2-5)=0,

⅓a+4b+9bc/2-15c=0,

4b+9bc/2=15c-⅓a,

b(4+9c/2)=15c-⅓a,

b=(15c-⅓a)/(4+9c/2),

Multiply top and bottom by 6:

b=(90c-2a)/(24+27c),

Or this can be written: b=⅔(45c-a)/(8+9c).

ago by Top Rated User (677k points)

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