solving 3 equations in algebra 2 by elimination
in Algebra 2 Answers by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

A: -6a-3b-3c=-27, 2a+b+c=9

B: 6a-b+c=27

C: 3a-b-5c=-18

D: A+B=8a+2c=36; E: A+C=5a-4c=-9

2D+E=16a+5a=72-9=63; 21a=63, a=3, so 15-4c=-9, 4c=24, c=6, so b=9-6-6=-3.

Therefore a=3, b=-3, c=6.
by Top Rated User (1.2m points)

Related questions

1 answer
asked Sep 25, 2013 in Algebra 1 Answers by anonymous | 926 views
1 answer
asked Jun 9, 2013 in Algebra 2 Answers by anonymous | 3.0k views
1 answer
asked Jan 31, 2012 in Pre-Algebra Answers by anonymous | 1.7k views
1 answer
asked Feb 21, 2019 in Trigonometry Answers by Gay boi | 4.1k views
1 answer
asked Sep 10, 2019 in Algebra 1 Answers by flatcat | 1.4k views
1 answer
asked Oct 22, 2012 in Algebra 1 Answers by anonymous | 968 views
1 answer
asked Feb 20, 2013 in Algebra 1 Answers by anonymous | 798 views
1 answer
2 answers
asked Aug 20, 2013 in Algebra 1 Answers by anonymous | 946 views
Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
87,516 questions
100,279 answers
2,420 comments
731,623 users