If r=<x,y> and s=<2,2>What is the graph of |r-s|=1

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This is the graph of a circle radius 1 and centre at   (2,2). Here’s why:

Let z=r-s=<x-2,y-2>, |z|=√z²=√((x-2)²+(y-2)²)=1. Square both sides:

(x-2)²+(y-2)²=1 is a circle centre (2,2), radius 1.

by Top Rated User (1.2m points)

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