12y^3+14y^2-40y

Factorise 12y^3+14y^2-40y
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2y(6y²+7y-20)=2y(3y-4)(2y+5). List the factors of 6 and factors of 20 and use them as coefficients and constants, testing each of them with cross-multiplication so that the middle term comes out as +7. Alternatively, apply the quadratic formula.

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