xdx - square root of (a2-x2) dy=0

elementary differential equations
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Rewritten, this is: dy=xdx/√(a²-x²).

Let u²=a²-x², 2udu=-2xdx, xdx=-udu.

dy=-du, integrating: y=-u+C, where C is constant of integration.

y=C-√(a²-x²).

by Top Rated User (1.2m points)

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