(A+1)(3a-5)=0

0=9c^2-16
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1 Answer

0=9c²-16=(3c+4)(3c-4), solution is c=-4/3 or 4/3.

(a+1)(3a-5)=3a²-5a+3a-5=3a²-2a-5, solution is a=-1 or 5/3.

by Top Rated User (1.2m points)

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