11x^3-65x^2-83x-7;(x+1)

Question

i dont know how to solve this problem

Answer 1

x+1 is a factor of the cubic. When we divide by it using algebraic or synthetic division we get 11x²-76x-7 as the other factor. This factorises into (11x+1)(x-7). So complete factorisation is (x+1)(x-7)(11x+1).

The zeroes, if needed, are -1, 7 and -1/11.