(2x²+3x-5)+(x²+11x-7)=180

(2x²+3x-5)+(x²+11x-7)=180
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1 Answer

(2x^2 + 3x - 5) + (x^2 + 11x - 7) = 180
2x^2 + x^2 + 3x + 11x - 5 - 7 = 180
3x^2 + 14x - 12 = 180
3x^2 + 14x - 12 - 180 = 0
3x^2 + 14x - 192 = 0
3x^2 + 32x - 18x - 192 = 0
(3x^2 + 32x) - (18x + 192) = 0
x(3x + 32) - 6(3x + 32) = 0
(x - 6)(3x + 32) = 0
x - 6 = 0 or 3x + 32 = 0
x = 6 or x = -32 / 3
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