Find the units digit for the sum 13^25 + 4^81 +5^411 .
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The powers yield cycles of digits in the units (ones) position. All powers 5 end in 5. Odd powers of 4 end in 4. And the cyclic pattern for 13 is (3 9 7 1), so 25/4 has a remainder of 1 so the last digit is 3.

Add these together: 3+4+5=12 so the last digit is 2.

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