Question

find the value of x for which the distance between the points (x,-5) and (2,7) is 13 units.

Answer 1

(x,-5) & (2,7)

want distans=13

distans=root(deltax^2 +deltay^2)

deltax=2-x......deltax^2=x^2-4x+4

deltay=7-(-5)=12

deltay^2=144

distans^2=13^2=169

(x^2-4x+4) +144=169

so  x^2 -4x =169-144-4=21

or x^2 -4x -21=0

x=7 or -3....take 7

points: (7,-5) & (2,7)

7-12-13 rite triangel

Answer 2

make that 5-12-13 rite triangel