What is the slope of the tangent line through (3,2) and (x,y) for x=-2 and y=x3.

Please help ASAP. Thanks!
in Calculus Answers by Level 2 User (1.0k points)

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1 Answer

I assume you mean the slope of the line rather than the tangent line, since (3,2) is not on the curve y=x³.

When x=-2, y=(-2)³=-8. So (x,y)=(-2,-8).

The slope of the line is (2-(-8))/(3-(-2))=10/5=2.

by Top Rated User (1.2m points)

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