What is the slope of the tangent line through (0,-3) and (x,y) for y = 3x^2 - 3 and x=1?

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1 Answer

since x=1 then y=3(1)*2-3=0 so the line passes through the points (0,-3) and (1,0) so the slope is

((0-(-3))/(1-0) = 3/1 =3
by Level 5 User (13.1k points)

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