Y intercept is [0;2], A[2;10], formula is f(x)=a×+q, asymptote is y=1
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There seems to be something wrong with the question because a linear equation has no asymptote.

But I can answer the remaining part of the question. The y intercept is when x=0 so q=2.

The line passes through (2,10) so 10=2a+2, 2a=10-2=8, so a=4 and f(x)=4x+2.

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