a ball thrown from the top row of seats. the function h(t)=16t^2+80t+96 give the hight in feet, of the ball t seconds after it is thrown. how long does it take before the ball hits the ground?
in Algebra 2 Answers by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

When h(t)=0 the ball reaches the ground, so 16(t²+5t+6)=0, so t²+5t+6=0=(t+3)(t+2)  which gives us negative values for t, so I suspect that 16t² should be -16t².

So we would have -t²+5t+6=0, that is, t²-5t-6=0=(t-6)(t+1) and t=6 seconds is the time the ball takes to reach the ground. We ignore t=-1 as meaningless (time before the ball was thrown).

The constant 96 feet is the height of the top row of seats. -16t² is the negative effect of gravity on the ball and  80 feet per second is the vertical component of the speed the ball was thrown. This is how h(t) was constructed.

by Top Rated User (716k points)

Related questions

Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
84,485 questions
89,386 answers
7,999 users