Each person, in an IT department of 60 people, works on at least one of 3 major projects: system security (ss), program implementation (pi), platform development. 23 people work on (ss), 28 on (pi), and 26 on (pd). 7 people work on (ss) and (pd). 12 work on (pi) and (pd). 6 people work on all 3 projects. How many people work only on (ss) and (pi)? (i.e. not all 3 projects)

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1 Answer

We can assign variables to numbers of people involved in one or more projects:

A ss only

B pi only

C pd only

D ss+pi

E ss+pd

F pi+pd

G all three projects

We know that each person is involved in at least one project, so:

A+B+C+D+E+F+G=60

A+D+E=23 (ss) }

B+D+F=28 (pi)  } excludes those working on all three*

C+E+F=26 (pd) }

E=7, F=12, G=6

A+D=23-7=16=28-12=B+D so B=A, D=16-A

C=26-(7+12)=7

2A+7+(16-A)+7+12+6=60,

A+7+16+7+12+6=60,

A=60-48=12 and D=16-A=16-12=4.

So (A,B,C,D,E,F,G)=(12,12,7,4,7,12,6), therefore 12 work on each of ss and pi and 7 work on pd.

* If the figures were to include those involved on all 3 projects, we get a negative result for one group of people, so there would be no sensible solution. The solution to this question depends on the interpretation of the figures provided.

by Top Rated User (1.2m points)

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