No picture provided so assume right triangle.
If z=hypotenuse=19cm, y=19sin27=8.6cm or y=19cos27=16.9cm.
If z=19cm as one leg, y is either the other leg or the hypotenuse.
So y=19tan27=9.7cm or 19tan63=37.3cm for y and z being legs.
Or y=19/sin27=41.9cm or y=19/cos27=21.3cm if y is the hypotenuse.
There are 3 possible positions for z and for each of these there are two possible positions for y, hence 6 possible solutions.