Kinetic energy of vehicle where m=mass and v=velocity is ½mv².

If 0.56 is µ, the coefficient of friction, the frictional force is µmg=17.92m where g=32ft/s².

The work done by friction=537.6m acting over 30 feet.

This counterbalances the KE of the vehicle so 537.6m=½mv². So v²=1075.2 and v=32.79fps=22.36mph approx. (36kph).

- All categories
- Pre-Algebra Answers 12,288
- Algebra 1 Answers 25,179
- Algebra 2 Answers 10,407
- Geometry Answers 5,145
- Trigonometry Answers 2,632
- Calculus Answers 5,937
- Statistics Answers 3,012
- Word Problem Answers 9,992
- Other Math Topics 6,534

81,126 questions

85,200 answers

2,143 comments

68,618 users