A+B+C complete the job in 60 hours. A takes twice as B, B takes 8 hours more to complete a job. Find the hours taken by A,B,&C individually.

Question

It is given under logical reasoning.

Answer 1

Assume B takes 8 hours more than C to complete the job.

A=2B, B=C+8, so A=2(C+8)=2C+16.

If we add their hours together we have A+B+C=2C+16+C+8+C=60.

4C=60-16-8=36. So C=9, B=17, A=34.