*×-2/×^2+3×-10 i have to write out and find excluded values*

The expression is,

(x - 2)/(x^2 + 3x - 10) -- the denominator factorises to give,

(x - 2) / {(x - 2)(x + 5)} -- cancel out common factors, to give

1 / (x + 5)

For this final expression, x can take any value except x = -5

For the original expression, (x - 2) / {(x - 2)(x + 5)}, at x = 2, we end up with 0/0 (zero divided by zero), which is not allowed.

So, although we can't give the original expresion a value at x = 2, which makes x = 2 an excluded value, we can give it a limit at x = 2.

Limit [x -> w] (x - 2) / {(x - 2)(x + 5)} = 1/7

**Excluded values are: x = 2, x = -5**

- All categories
- Pre-Algebra Answers 12,315
- Algebra 1 Answers 25,275
- Algebra 2 Answers 10,441
- Geometry Answers 5,178
- Trigonometry Answers 2,639
- Calculus Answers 6,003
- Statistics Answers 3,018
- Word Problem Answers 10,104
- Other Math Topics 6,644

81,617 questions

85,852 answers

2,186 comments

69,284 users